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[tex] \frac{ \sqrt{8}+2 }{ \sqrt{8}-2 } = \frac{ \sqrt{2}+1 }{ \sqrt{2} -1} [/tex]

Răspuns :

[tex] \frac{ \sqrt{8}+2 }{ \sqrt{8}-2}= \frac{2 \sqrt{2}+2 }{2 \sqrt{2}-2 }= \frac{2( \sqrt{2}+1 )}{2( \sqrt{2}-1 )}= \frac{ \sqrt{2}+1 }{ \sqrt{2}-1 } [/tex]