[tex] \frac{c}{5}= \frac{b}{5} = \frac{a}{6}= \frac{a+b+c}{5+5+6} = \frac{128}{16}=8 \\ c=b=40 \\ a=48 [/tex]
Daca tr este ABC duci inaltimea AD si aplicam Pitagora in tr. ADB
AD=32 (24,32,40 sunt numere pitagorice)
[tex]A= \frac{BC\cdot AD}{2} = \frac{48\cdot 32}{2}=768 cm^{2} [/tex]
