1)x-oul de strut, y-oul de gaina
9kg=9000g
3x+60y=9000
x=20y inlocuim in prima relatie
3·20y+60y=9000
120y=9000
y=9000/120=75 g cantareste oul de gaina
x=20·75
x=1500 g oul de strut
4)
x_Maria, y_mama
{x+y=86 inmultim cu -2⇒ {-2x-2y=-172
{2x+3y=220 {2x+3y=220, se reduce x⇒
-2y+3y=220-172
y=48 coltunasi a facut mama intr-o ora
x=86-48
x=38 xotunasi a facut maria intr-o ora