[tex]Notatii: \\ a = numarul \;fetelor\;vopsite\;in\;albastru. \\ g=numarul \;fetelor\;opsite\;in\;galben \\ p_a = \text{probabilitatea aparitiei unei fete albastre}\\ p_g = \text{probabilitatea aparitiei unei fete galbene} \\ \\ \text{Un cub are 6 fete} \\ \\ Rezolvare: \\ p_a = \frac{nr cazuri favorabile}{nr total de cazuri}= \frac{a}{6} = \frac{1}{3} \;\;\; =\ \textgreater \ \;\;\; a= \frac{6*1}{3}= \frac{6}{3}=\boxed{2 \;fete\;albastre}[/tex]
[tex] p_g = \frac{nr cazuri favorabile}{nr total de cazuri}= \frac{g}{6} = \frac{2}{3} \;\; =\ \textgreater \ \;\;g= \frac{6*2}{3}= \frac{12}{3}=\boxed{4 \;fete\;galbene}[/tex]
