1) Cele patru numere consecutive sunt x,x+1,x+2,x+2
Produsul primelor doua este :x(x+1)=72 =8*9⇒
x=8 x+1=9 x+2=10 x+3=11
2) Ma(a,b)=(a+b)/2=133,5 ⇒
a+b=133,5*2=267
Mg(a,b)=√ab=120⇒ a*b=120²=14400
a=267-b
(267-b)*b=14400
267b-b²-14400=0
Δ=b²-4ac=267²-4*14400=71289-57600=13689
√Δ=117
b1=(-b-√Δ)/2a
b2=(-b+√Δ)/2a
b1 = 75
b2 = 192
=>a1=267-75=192
a2=267-192=75
Numerele sunt 192 si 75
