1)
m=20kg; F=220N
Randamentul η=Lutil/Lconsumat
Lutil=mgh; Lconsumat=Fh
η=mgh/Fh=mg/F=20×10/220=200/220=2/2,2=0,9
Sau in procente η=90%
2)
m=40Kg; h=0,5m; l=1,75m; F=140N
η=Lutil/Lconsumat
Lutil=mgh
Lconsumat=Fl
η=mgh/Fl=40×0,5×10/140×1,75=200/245=0,81=81%
3).Fiindca exista frecari care consuma energie.