a)2NH3(g) + Q -> N2(g) + 3H2(g)
b)
2moli........1mol
2NH3(g) -> N2(g) + 3H2(g)
4moli.......x=2moli
c)
1mol NH3.............92kJ absorbiti
d)
2moli......................3moli
2NH3(g) -> N2(g) + 3H2(g)
x=4moli..................6moli
1mol NH3..............92kJ absorbiti
4moli NH3...............ykJ absorbiti
y=4*92=368kJ absorbiti