[tex](x+7)^{2} =(5-x)*(3x+11)
x^{2} +14x+49=15x+55-3x^{2}-11x
x^{2} +14x+49-15x-55+3x^{2}+11x=0
4x^{2}+10x-6=0
a=4
b=10
c=-6
delta= 10^{2}-4*4*(-6) =196
x_{1}= \frac{-10+14}{8}= \frac{4}{8} = \frac{1}{2}
x_{2}= \frac{-10-14}{8}= \frac{-24}{8}=-3 [/tex]
