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Cum se rezolva : √(4-2√3) = ?

Răspuns :

[tex] \sqrt{(4-2 \sqrt{3} )} = \sqrt{(1+3-2 \sqrt{3} )}= \sqrt{(1^{2}+( \sqrt{3}) ^{2}-2 \sqrt{3} )}= \\ \sqrt{(1- \sqrt{3)}^{2} } =|1- \sqrt{3} |= \sqrt{3} -1[/tex]