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Calculati
(2x+3)²-(2x-3)(2x+3)+2(x-1)²
Va rog ajutati-ma dau coroana!!!!


Răspuns :

⇔4x²+12x+9-4x²+9+2x²-4x+2=2x²+8x+20
(2x+3)²=(2x)²+2×2x×3+3²
          =4x²+12x+9
(2x-3)(2x+3)=(2x)²-3² =4x²-9
(x-1)²=x²-2x+1

4x²+12x+9-4x²-9+2×x²-2x+1 ..(+4x² si -4x² ;+9 si -9  se reduc)
12x+2x²-2x+1