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Fie functia f: R-> R, f(x)= 3 -2x. Rezolvati inecuatia f(x) +4< f(2x) , x ∈ R.

Răspuns :

3-2x+4<3-4x
-2x+4x<3-3
2x<0
x<0
x∈R
⇒x∈(-infinit,0)
3-2x+4 < 2(3-2x), 7-2x < 6-4x, -2x + 4x < 6-7, 2x < -1, X < - 1/2 ; x € (-infinit, - 1/2)