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Determinati numerele naturale a,b,c astfel incat numerele a supra 9,b supra 12,16 supra c si 0,(6) sa reprezinte acelasi numar rational.

Răspuns :

a/ 9 = b /12 = 16/c = 6/9 = 2/3 
a/9 = 2/3 daca a = 9·2 / 3 = 18 /3 =6 
b /12 = 2/3   ; b =12· 2 /3 = 8 
16/ c = 2/3   ; 2c = 16·3   ; c =24
a/9=b/12=16c=6/9=2/3
⇒a/9=2/3⇒a=9·2/3⇒a=3·2⇒a=6;
⇒b/12=2/3⇒b=12·2/3⇒b=6·3⇒b=18;
⇒16/c=2/3⇒c=16·3/2⇒c=8·3⇒c=24;