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Aduceti ecuatiile urmatoare la forma ax²+bx+c=0 si apoi rezolvatile:
a)3x(x-1)+4x-4=0
b)(x-2)(x+2)=3x
c)2x(x+1)-x(x+4)-3=0
d)4x(x+2)=2(4x-3)


Răspuns :

a) 3x(x-1)+4x-4=0=> 3x^2-3x+4x-4=0=> 3x^2+x-4 Delta=1+48=49 X1=(-1+7)/6=1 X2=(-1-7)/6=-4/3 B) (x-2)(x+2)=3x=> X^2-3x-4=0 Delta=9+16=25 X1=(3+5)/2=4 X2=(3-5)/2=-1 C) 2x(x+1)-x(x+4)-3=0=> 2x^2+2x-x^2-4x-3=0=> x^2-2x-3=0 Delta=4+12=16 X1=(2+4)/2=3 X2=(2-4)/2=-1 D)4x(x+2)=2(4x-3)=> 4x^2+8x=8x-6=> 4x^2-6=0