notezi latura patratului cu a si dimensiunile cu l si L
l+5=[tex] \frac{1}{3} [/tex]a =>a=(l+5)3=3l+15
P patrat= 4a=4(3l+15)=12l+60
P drept.=2l+2L
2L+2l+12=[tex] \frac{1}{2} [/tex]4a=[tex] \frac{1}{2} [/tex](12l+60)=6l+30
=>2L=6l+30-2l-12=4l+18=>L=2l+9
2L+2l-4a=96=>4l+18+2l-12l-60=-6l-42=96=>-6l=138=>l=-23=>L=2l+9=9-46=-37