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Solutia numar natural a ecuatiei 10x+11x+12x+....+99x=9810 este
a) 2
b) 0
c) 1
d) 3


Răspuns :

folosim formula 1+2+3+4+...+n=[tex] \frac{n*(n+1)}{2} [/tex]

1+2+3+4+...+99=[tex] \frac{99*100}{2}= 4950[/tex]
1+2+3+4+...+9=[tex] \frac{9*10}{2}=45 [/tex]

10+11+12+...+99=4950-45=4905

10x+11x+12x+...+99x=9810
x(10+11+12+...+99)=9810
4905x=9810
x=9810:4905
x=2