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32-paranteza acualada 12+paranteza patrata 40-(16:8+4ori 9):2 închidem paranteza patrata si acualada :3=

Răspuns :

 32-{12+[40-(16/8+4*9)÷2]}÷3=
=32-{12+[40-(2+36)÷2]}÷3=
=32-{12+[40-38÷2]}÷3=
=32-{12+[40-16]}÷3=
=32-{12+24}÷3=
=32-36÷3=
=32-12=
=20