1.
x+y=300 y=300-x
4(x+5)=(y-5)
4x+20=300-x-5
5x=275
x=55 l in primul vas
y=300-55=245 l in al 2-lea vas
2.
a=l vas 1
b=l vas 2
c=l vas 3
d cantitatea scoasa = b/2
b-d=d ⇒ d=b/2
a-b/2=3b/2 a=2b
c-d=3/8(a-b/2+b-b/2) = 3a/8=3*2b/8=3b/4
a+b+c=170
2b+b+3b/4=170
8b+4b+3b=680
15b=680
b=45,(3)
a=45,(3)*2=90,(6)
c=3*45,(3)/4=33,(9)