A+B+C=?
204-cel mai mic nr de trei cifre pare nenule
A÷B=2rest C=>A=B×C+2⇒A=2×C+20
B=C+20
A+B+C=204
C+20=B
2×C+20+C+20+C=204
4×C+20+20=204
4×C+40=204
4×C=204-40
4×C=164
C=164÷4
C=41
B=41+20
B=61
A=2×41+20
A=82+20
A=102
Raspuns: A=102;B=61;C=41
Sper sa-ti fie de ajutor!