daca ΔABC este dreptunghic in A si m(B)=60 ⇒masura unghi c=30 grade⇒ab=bc/2
daca ab=12⇒12=bc/2⇒bc=12×2
bc=24
ac²+ab²=bc²
ac²=bc²-ab²
ac²=24²-12²
ac²=576-144
ac²432⇒ac=√432⇒ac=12√3
perimetrul abc=ab+ac+bc
perimetrul abc=12+24+12√3
perimetrul abc=36+12√3=13(3+√3)
duc ad perpendicular pe bc cu d apartine lui bc
aplic teorema catetei
ab²=bc×bd
12²=24×bd
144=24×bd⇒bd=144/24⇒bd=6
cd=bc-db⇒cd=24-6⇒cd=18
teorema inaltimii:
ad²=cd×cd
ad²=6×18
ad²=108⇒ad=√108⇒ad=6√3
arie Δabc=ad×bc/2
arie Δabc=6√3×24/2
arie Δabc=6√3×12
arie Δabc=72√3
