98/100=Vpur/457,143 => Vpur=457,143*0,98=448m3 => n=Vpur/22,4=20kmoli
1kmol....22,4L........1kmol
C2H2 + HCl -> CH2=CH-Cl
20kmoli..y=?........20kmoli
90/100=x/20 => x=20*0,9=18kmoli
1000kmoli.................62,5*1000kg
1000CH2=CH-Cl -> (-CH2-CH(Cl)-)1000
18kmoli....................z=1125kg
y=20*22,4=448m³ HCl(fara exces)
448m³..........100%
t....................110%
t=448*1,1=492,8m³ HCl