👤

Perimetrul unui triunghi este egal cu 9 dm.Aflati lungimile laturilor triunghiului stiind ca ele sunt direct proportionale cu numerele 5,12,13.
SOS


Răspuns :

P=9 dm
AB,AC,BC d.p 5,12,13
9 dm=9.10=90 cm
AB=5K
AC=12K
BC=13K
AB+AC+BC=90 cm
5k+12k+13k=90
30k=90
k=90:30
k=3
AB=5.k=5.3=15 cm
Ac=12.k=12.3=36 cm
BC=13.k=13.3=39 cm



PERIMETRULtriunghi=AB+BC+AC=9DM
[tex] \frac{AB}{5} [/tex]=[tex] \frac{BC}{12} [/tex]=[tex] \frac{AC}{13} [/tex]⇒[tex] \frac{AB+BC+AC}{5+12+13} [/tex]=[tex] \frac{PERIMETRU TRIUNGHI}{30} [/tex]=[tex] \frac{9}{30} [/tex]
[tex] \frac{AB}{5}= \frac{9}{30} [/tex]⇒AB=[tex] \frac{45}{30} dm [/tex]
[tex] \frac{BC}{12} [/tex]=[tex] \frac{9}{30} [/tex]⇒BC=[tex] \frac{108}{30} [/tex]dm
[tex] \frac{AC}{13}= \frac{9}{30} [/tex]⇒AC=[tex] \frac{117}{30} dm[/tex]