Formula sulfatului de potasiu : [tex] K_{2} S O_{4} [/tex]
Calculam masa molara : [tex]M_{ K_{2}S O_{4} } = 2 * 39 + 1 * 32 + 4 *16= 78 + 32 + 64=174 g... K_{2} SO _{4} [/tex]
1 mol sulfat de potasiu .................. 174g sulfat de potasiu
0.2 moli sulfat de potasiu............... x g sulfat de potasiu
=> x= 0.2 * 174
x= 34.8 g sulfat de potasiu
[tex]c= \frac{ m_{d} }{m_{s} } * 100 =\ \textgreater \ m_{s} = \frac{m_{d}* 100 }{c } = \frac{34.8 * 100}{10} = 348 \\ m_{s} =348g...solutie....sulfat...de...potasiu.[/tex]
