a+b=4,(7).2=[tex] \frac{86}{9} [/tex]
b+c=8,(6).2=[tex] \frac{156}{9} [/tex]
a+c=[tex]3,(2).2= \frac{58}{9} [/tex]
Adunam relatiile si obtinem dupa impartirea cu 2 :
a+b+c=[tex] \frac{150}9} [/tex]
de unde a=[tex] \frac{150}9}- \frac{156}{9} = \frac{-6}{9} [/tex]
b=[tex] \frac{150}{9}- \frac{58}{9} = \frac{92}{9} [/tex]
c=[tex] \frac{150}{9} - \frac{86}{9}= \frac{64}{9} [/tex]
Daca esti clasa a 5-a atunci undeva este o greseala...Mai verifica textul...
