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Suma a patru numere consecutive este 420.Aflati cele patru numere.

Răspuns :

a+b+c+d=420
b=a+1
c=a+2
d=a+3
a+a+1+a+2+a+3=420
4a+6=420
4a=420-6
4a=414
a=103,5
b=103,5+1=104,5
c=103,5+2=105,5
d=103,5+3=106,5
a
a+1
a+1+1
a+1+1+1
a=420-1-1-1-1-1-1=414
414:4=103.5
103.5+1.4.4+105.5+106.5=420