pt ultima problema: rezolvare:
- cateta opusa unghiului de 30 de grade este egala cu jumatate din ipotenuza
[tex] AB=\frac{BC}{2} [/tex]
[tex] \frac{BC}{2} =12 =\ \textgreater \ BC=12*2=24[/tex]
[tex] sin 60 = \frac{cateta opusa}{ipotenuza} =\ \textgreater \ \frac{AC}{BC} = \frac{ \sqrt{3} }{2} [/tex]
[tex] \frac{AC}{24} = \frac{ \sqrt{3} }{2} =\ \textgreater \ 2AC=24 \sqrt{3} =\ \textgreater \ AC= \frac{24 \sqrt{3} }{2} =\ \textgreater \ AC=12 \sqrt{3} [/tex]
[tex]A = \frac{AB*AC}{2} = \frac{12 \sqrt{3} *12}{2} = 72 \sqrt{3} cm^{2} [/tex]
P = [tex]12 \sqrt{3} +12+24 = 12 \sqrt{3} +36 cm[/tex]
