[tex]CH_{3} -CH_{3} =\ \textgreater \ CH_{2} =CH_{2} + H_{2} [/tex]
[tex] CH_{3}- CH_{3} =\ \textgreater \ CH_{3}- CH_{3}[/tex]
am gazon final : C2H6 , C2H4, H2
luam 100 moli am gazos final ⇒ 20 moli H2 , 20 moli C2H4 , 40 moli C2H6
din r. ch ⇒ 20 moli C2H6 reactionati
avem 40 moli exces ⇒ initial 40+20 = 60 moli etan
60 moli etan _____ se descompun 20
100 ____________ p= 33,33 %