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Aratati ca numarul a=√2(√18+√32--2√8).

Răspuns :

[tex]a= \sqrt{2} ( \sqrt{18} + \sqrt{32} -2 \sqrt{8})= \\ = \sqrt{36} + \sqrt{64} -2 \sqrt{16}= \\ =6+8-2*4= \\ =6. [/tex]

a=6=> a∈N.