[tex]2NaOH + H _{2} S O_{4} -\ \textgreater \ Na_{2} S O_{4} + 2H_{2} O[/tex]
Din formula
n acid sulfuric=md/M=49.98/40=1,24 moli NaOH intra in rc.
md de acid sulfuric=98*50/100=49 g intra in rc.
n acid sulfuric=49/98=0.5 moli
Din reactie avemx/2=0.5/1=> x=1, unde x-nr de moli de solotie NaOH (soda caustica)
n=md soda/M => md soda= 40*1=40 g sol.
Din formula conc => ms soda=100md/c=100*40/30=133,3 g
Fie y-nr de moli de H2O.
y/2=1/2 pe rc. => y=1 mol de apa=> 18 g H2O la sf. rc.
n sulfat de sodiu=md/M
n din rc=0.5
=> md=Mn=0.5*142=71 g sulfat de sodiu
ms=m apa +m sulfat= 18+71=89 g
c=100*md/ms=100*71/89=79,77 %
