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Rezolvati urmatorul sistem de ecuatii (prin metoda reducerii): 2010x + 2011y=2011 ; 2011x +2010y=2010. Multumesc anticipat.

Răspuns :

{2010x+2011y=2011 | X (-1)   (X mare e inmultit)         <=>
{2011x+2010y=2010

{-2010x-2011y=-2011|
{2010x+2010y=2010 |     <= aici e o linie mare,unita pe vertical
 _________________ |
    /     -1y     =-1
            y      = 1

2010x+2011(+1)=2011
2010x+2011=2011
2010x=-1
x= -2010/1