f(x)=(5-x)/2
5-x=0
-x=-5 inmultim -1
x=5
g(x)=5x+1
5x+1=0
x=-1/5
a) F(0)=(5-0)/2=5/2
f(0)=5/2
g(0)=5·0+1=1
g(0)=1
f(x)≥g(x)
f(1)=2 g(1)=6
f(2)=3/2 g(2)=11
f(-1)=3 g(-1)=-4
f(-2)=7/2 g(-2)=-9
pt.x∈(-α, 0] f(x)>g(x)
pt.x∈(1,+α), f(x)<g(x)
g(x) nu este niciodata egal cu g(x)
