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Amplificati raportul algebric √3x-4 supra √3x+4 cu 4-√3x.Va rog mult.Mulumesc anticipat )

Răspuns :

(x√3-4)/(x√3+4)  ×( 4-x√3)/(4-x√3) =
=(x√3-4)( 4-x√3)/(x√3+4)( 4-x√3) =
=-(x√3-4)(x√3-4)/(4+x√3)( 4-x√3) =
=-(3x²-8x√3+16)/(16-3x²)=
=(3x²-8x√3+16)/(3x²-16)