a ∈ N
consecutive
a , a+1 , a +2
a + a+1 + a+ 2 = ..........2014
3· a + 3 = .......2014
3·a= .......2014 -3
3·a= ---------2011
in fata trebuie pus cel mai mic numar natural care se imparte la 3
fie 3· a= 12011 dar 12011:3=4003,66 fals
fie 3· a= 22011 dar 22011:3= 7337 adevarat
7337, 7338 ,7339