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a= 2· (8+√8 ) -3· (4+√8)
a=?


Răspuns :

[tex]16+2 \sqrt{8} - 12-3 \sqrt{8} =14 - \sqrt{8} [/tex]
     
[tex]a=2(8+ \sqrt{8} )-3(4+ \sqrt{8})= \\ =2(8+ 2\sqrt{2} )-3(4+ 2\sqrt{2})= \\ =16+ 4\sqrt{2}-12- 6\sqrt{2}= \\ =16-12+ 4\sqrt{2}- 6\sqrt{2}= \\= 4-2\sqrt{2}= \boxed{2(2-\sqrt{2})}[/tex]