Ducem inaltimea piramidei si notam piciorul inaltimii cu O, si diagonalele bazei
ΔBCD-Δdrept (C=90 grade)
DB²=BC²+CD²=6²+6²=36+36=72
DB=√72=6√2
OD=OB=DB\2=6√2\2=3√2
ΔVOB-Δdrept (O=90 grade)
tgB=cat opusa\cat alaturata=OB\VO
1=3√2\VO => VO=3√2
Ab=l²=6²=36
V=Ab*VO\3=36*3√2/3=36√2cm³