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Daca a+b+c=119 si 2a supra 3 egal cu 3b supra 5 egal cu 5c supra 4.Determinati a , b, c.


Răspuns :

a+b+c=119
2a/3=3b/5=5c/4=k

a=3k/2,  b=5k/3,  c=4k/5

(45k+50k+24k) /30 =119
119 k =30 × 119
⇒k=30

⇒a= 3 ×30/2=45
  b= 5×30/3=50
  c=4 × 30/5 =24