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Rezolvat prin metoda substitutiei :
[tex] \left \{ {{X+3Y=1} \atop {2X+Y=7}} \right. [/tex]


Răspuns :

[tex] \left \{ {{x+3y=1} \atop {2x+y=7}} \right. \\ x+3y=1=>x=1-3y \\ 2(1-3y)+y=7 \\ 2-6y+y=7 \\ -5y=5=>y=-1 \\ x+3(-1)=1 \\ x-3=1=>x=4[/tex]

nu stiu daca am calculat corect adunarile/scaderile dar asta e metoda de rezolvare.