Vo=h=3[tex] \sqrt{3} [/tex]
AB=6 -----> OM=Apatra=[tex] \frac{AB}{2} [/tex]=3
in Triunghiul VOM masura O=90 grade -------> t pitagora VM^2=VO^2+OM^2
Vm^2=27+9
VM=[tex] \sqrt{36} [/tex]
Vm=6
P bazei =4AB
= 24
A lat = [tex] \frac{Pbaza X Apotema piramida }{2} [/tex]
= [tex] \frac{24X3 \sqrt{3} }{2} [/tex]
= 12x3[tex] \sqrt{3} [/tex]=36[tex] \sqrt{3} [/tex]
