1. Δl1=l1αΔt pentri sarma de 1m ⇒αΔt=Δl1/l1
Δl2=l2αΔt pentru sarma de 5m
Δl2=l2*Δl1/l1
Δl2=5*Δl1
Δl2=15 mm
2.
t=t1-t2=24-(-5)=29 grade
K=29+273,15=302,15
b)
58 grade C
F=(58x1,8)+32=136,4
K=58+273,15=331,15
6000 grade C
F=(6000x1,8)+32=10832
k=6000+273,15=6273,15
36,7 grade C
F=(36,7x1,8)+32=98,02
K=36,7+273,15=309,85
Calculele nu aveam cum sa le fac aici, imi pare rau :(, oricum Sper ca te-am ajutat!