(√5-2)x > √20-4
(√5-2)x > [tex] 2\sqrt{5} [/tex] - 4
(√5-2)x > 2([tex] \sqrt{5} - 2[/tex] )
x > [tex] \frac{2 ( \sqrt{5} - 2) }{ \sqrt{5} - 2} [/tex]
x > 2
x ∈ intervalului deschis 2 , plus infinit
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x(1-√2) ≥ 4- 2√8
[tex]x(1- \sqrt{2} ) \geq 4 - 2*2 \sqrt{2}
x(1- \sqrt{2} ) \geq 4 - 4 \sqrt{2}
x(1- \sqrt{2} ) \geq 4(1 - \sqrt{2})
x \geq \frac{4(1- \sqrt{2} )}{1 - \sqrt{2} }
x \geq 4
[/tex]
x ∈ intervalului inchis 4 , plus infinit
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|2x-1|≤3
[tex]-3 \leq 2x - 1 \leq 3[/tex]
Adunam 1 la fiecare termen -->
-2 ≤ 2x ≤ 4 /:2
-1 ≤ x ≤ 2
x ∈ multimii -1 , 0 , 1 , 2
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-1≤2-x≤5
Adunam -2 la fiecare termen -->
-3 ≤ -x ≤ 3 \(-1)
1 ≥ x ≥ -3
x ∈ multimii formata din numerele 1 si 0
