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Calculati:(3x+2)^2-5x(x-3)>(x-2)(x+2)

Răspuns :

(3x+2)^2=(3x)^2+2•3x•2+2^2=9x^2 + 12x+4 (x-2)(x+2)=x^2 - 2^2=x^2 - 4 Rezultatul:9x^2 + 12x+4-5x^2 + 15x> x^2 - 4=9x^2 - 5x^2 - x^2 + 27x > -4-4 = 3x^2 + 27x > -8