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Rezolva ecuatiile:
1-2 (x+1) = 3x+1
1 supra 2 - x+1 supra 3 = 6 supra 6
√2 (x+√2) = 3x-2 supra √2
2y + 1 supra 5- 1 supra 2= 1 supra 10 - 3y - 2 supra 2
1 supra 7 (3x-4) + 1 supra 3 (5x+3) = 1-2x
3 supra 4 (5x-2) - 1 supra 2(3x + 4 ) = 1


Răspuns :

1)
1-2(x+1)=3x+1
0=3x + 2x +1
5x=-1
x= -1/5
2)
1/2 - x + 1/3= 6/6
3/6 + 2/6= 1 + x
5/6 - 1=x
x = 5/6 - 6/6= -1/6
3)
√2(x+√2)=3x - 2/√2
√2(x+√2)= 3x√2/√2 - 2/√2
√2(x+√2=(3x√2 - 2)/√2
2(x+√2)=3x√2 - 2
2x + 2√2 +2 = 3x√2
2x -3x√2 +2√2 +2 =0
x(2-3√2) +2(√2+1)=0
x = - [2(√2+1)]/(2-3√2)
 nu cred ca e bine cum am facut la asta
4)
2y + 1/5 - 1/2 = 1/10 - 3y - 2/2
2y+3y = 1/10 + 1/2 - 1/5 -2/2
5y= 1/10 + 5/10 - 2/10 -10/10
5y = - 6/10
y= -6/50
5)
1/7 * (3x-4) + 1/3 * (5x+3) = 1-2x
[3(3x-4)]/21 + [7(5x+3)]/21 = 1 - 2x
(9x - 12 + 35x +21)/21= 1 - 2x
44x + 9 = 21 - 42x
86x=12
x= 6/43
6)
3/4(5x-2) - 1/2(3x+4) = 1
[3(5x-2) - 2(3x+4)]/4=1
15x - 6 -6x - 8 = 4
9x -14=4
x=18/9=2