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Aflati numerele a,b si c stiind ca sunt invers proportionale cu numerele 2,3 si 8 si ca 5a+3b-2c=a56

Răspuns :

{a,b,c}ip{2,3,8}
2a=3b=8c=k
a=k/2
b=k/3
c=k/8
5a+3b-2c=156
5k/2+3k/3-2k/8=156
5k/2+k-k/4=156
(10k+4k-k)/4=156
13k=156·4
k=624/13
k=48
a=k/2=48/2
a=24
b=k/3=48/3
b=16
c=k/8=48/8
c=6