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(x+1)^2+(x-2)^2=2(x-1)(x+3)-1


Răspuns :

x²+2x+1+x²-4x+4=2(x²+3x-x-3)-1
2x²-2x+5=2x²+6x-2x-6-1
-2x+5=4x-7
-2x-4x=-7-5
-6x=-12
6x=12
x=2
x^2 +2x+1+x^2-4x+4=2x^2+6x-2x-6-1
-6x+12=0
-6x=-12
x=2