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calculati x din proportiile
a) [tex] \frac{x-1}{1+ \frac{1}{2} } = \frac{ \frac{7}{3}-1 }{3- \frac{3}{2} } , x[/tex]∈Q
b) [tex] \frac{2x+1}{4x+3} = \frac{1}{3}[/tex] , x apartine Q \{[tex] {- \frac{3}{4} }[/tex]}


Răspuns :

7/3-1=(7-3)/3=4/3
1+1/2=3/2
3-3/2=6-3/2=3/2
(x-1)/(3/2)=(4/3)/(3/2)
x-1=4/3
x=4/3+1
x=7/3

(2x+1)/(4x+3)=1/3
6x+3=4x+3
6x=4x
x=0