deci 0,2=2/10=1/5
scriu x ca fiind invers proportional cu 1/5 asa x/1/1/5 adica x/1:1/5=x/1 ori 5/1=5x
0,5=5/10=1/2
scriu y ca fiind invers proportional cu 1/2 asa
y/1/1/2=y/1:1/2=y/1 ori 2/1=2y
acum stim ca 5x=2y⇒x=2y/5
suma dintre dublul primului si triplul celuilalt este 84
2x+3y=84
2×2y/5+3y=84
4y/5+3y=84
4y/5+5×3y/5=84
4y/5+15y/5=84
19y/5=84
19y=84×5
19y=420
y=420/19
x=2y/5
x=2×420/19/5
x=840/10/5
x=840/19:5=840/19×1/5=168/19