👤

Solutia reala a ecuatiei ( √3x+2) la a doua=3(x-√3) la a doua+25 este egala cu..?

Răspuns :

(x√3+2)²=3(x-√3)²+25
ridicand la patrat⇒3x²+4√3x+4=3x²-6√3x+9+25
reducand termeni asemenea ⇒10x√3=30
x=30.√3/10.3⇒x=√3