[tex]3x^2-x-2=3x^2-3x+2x-2=3x(x-1)+2(x-1)=[/tex]
[tex]=(x-1)(3x+2)[/tex]
SAU:
Rezolvi ecuatia [tex]3x^2-x-2=0;\ \ \Delta=25;\ \ x_1=1;\ \ \ x_2=-\dfrac23[/tex] si folosesti formula:
[tex]ax^2+bx+c=a(x-x_1)(x-x_2)[/tex]. Obtii:
[tex]3x^2-x-2=3(x-1)(x+\dfrac23)=(x-1)(3x+2)[/tex]