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aflati valoarea raportului algebric 3x+2y pe 2x-y pentru:a) x=y=1; b)x=4,y=2; c)x=1pe6, y=1pe2; d)x=-0.8; y=0.4.

Răspuns :

a. (3x+2y)/(2x-y)=5/1=5
b.(3x+2y)/(2x-y)=16/6=8/3=2 2/3
c. (3x+2y)/(2x-y)=(1/2+1)/(1/3-1/2)=(3/2)/(2/6-3/6)=3/2:1/6=3/2·6=9
d. (3x+2y)/(2x-y)=(-2,4+0,8)/(-1,6-0,4)=-1,6/(-2)=+0,8