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va rog ajutatiman
rezolvati in R ecuatia:2(3x-2)+3(4-2x)


Răspuns :

2(3x-2)+3(4-2x)=(6x-4)+(12-6x)=6x-4+12-6x=12x=-16
x=[tex] \frac{-16}{12} ^{(4} [/tex]
x=[tex] \frac{-4}{3} [/tex]   sau x=[tex]1 \frac{1}{3} [/tex]