👤

1)Determinati lungimea ipotenuzei unui triunghi dreptunghic isoscel cu cateta de:
a) 8 cm;
b) 9√2 cm;
c) x cm.


Răspuns :

a) ipotenuza=√(8²+8²)=8√2
b) ipotenuza=√[(9√2)²+(9√2)²]=√324=18 cm
c) ipotenuza=√(x²+x²)=x√2
a)ipotenuza=[tex] \sqrt{64+64}= \sqrt{128} [/tex]=8[tex] \sqrt{2} [/tex]
b)ipotenuza=[tex] \sqrt{162+162}= \sqrt{324}=18 [/tex]
с)ipotenuza=[tex] \sqrt{ x^{2} + x^{2} }= \sqrt{2 x^{2} } =x\sqrt{2} [/tex]